Question 1055734
i have to 2 equations x+y=20 and 25x+15y=430. the end goal is to find how many of x and y there is. i think i need to cancel out the 15 but i dont know where to start. 
<pre>x + y = 20 ------- eq (i)
25x + 15y = 430 ------- eq (ii)
You can multiplying eq (i) by - 15 to ELIMINATE y and find the value of x
Then substitute value of x into eq (i) (easier of the 2) to get value of y
OR
Divide eq (ii) by 5 to get: 5x + 3y = 86 ------ eq (ii). 
Then multiply eq (i) by - 3 to get eq (iii), which you then add to eq (ii) to ELIMINATE y and find the value of x.
You'd have 1 more equation to change but after all, you'd be dealing with smaller numbers. It's your choice though.