Question 1055690
if 4^x+1 =2^x-1 find x
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{{{4^x+1 =2^x-1}}}
{{{4^x - 2^x = -2}}}
{{{2^(2x) - 2^x + 2 = 0}}}
Sub u for 2^x
{{{u^2 - u + 2 = 0}}}
*[invoke solve_quadratic_equation 1,-1,2]
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No real number solutions.