Question 1055490
Rate*Time=Output
For the first machine,
{{{R[1]*3.3=1}}}
{{{R[1]=1/3.3}}}
For the machines together,
{{{(R[1]+R[2])*1.4=1}}}
Substituting,
{{{(1/3.3+R[2])*1.4=1}}}
{{{1/3.3+R[2]=1/1.4}}}
{{{R[2]=1/1.4-1/3.3}}}
{{{R[2]=10/14-10/33}}}
{{{R[2]=(10/14)(33/33)-(10/33)(14/14)}}}
{{{R[2]=(330-140)/(33*14)}}}
{{{R[2]=190/462}}}
{{{R[2]=95/231}}}
So then,
{{{R[2]*t=1}}}
{{{t=1/R[2]}}}
{{{t=231/95}}}{{{hr}}}