Question 1055662
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If the perimeter of a rectangle is 260 feet and the length is 30 feet more than the width, what are the dimensions of the rectangle?
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Let W be the width, then the length is W+30.

W + (W+30) + W + (W+30) = 260,

4W + 60 = 260,

4W = 260-60  --->  4W = 200  --->  W = {{{200/4}}} = 50.

<U>Answer</U>.  The wide is 50 ft.  The length is 50+30 = 80 ft.
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