Question 1055568
Let {{{A}}} and {{{B}}} be two integers 0-9 and
{{{N=10*A+B}}}
So,
{{{N*7=182}}}
{{{(10*A+B)7=182}}}
1.{{{10A+B=26}}}
and
2.{{{A+B=8}}}
Subtracting 2 from 1,
{{{10A+B-A-B=26-8}}}
{{{9A=18}}}
{{{A=2}}}
Then,
{{{2+B=8}}}
{{{B=6}}}
The number is 26.