Question 1055431
1.{{{(A+B+C+D+E+F+G+H+I+J)/10=13}}}
2.{{{(A+B+C+D+E+F)/6=14}}}
3.{{{(E+F+G+H+I+J)/6=11}}}
4.{{{F=(3/2)E}}}
From 1,
{{{A+B+C+D+E+F+G+H+I+J=130}}}
From 2,
{{{A+B+C+D+E+F=84}}}
Subtracting,
{{{A+B+C+D+E+F+G+H+I+J-A-B-C-D-E-F=130-84}}}
{{{G+H+I+J=46}}}
From 3,
{{{E+F+G+H+I+J=66}}}
Subtracting again,
{{{E+F+G+H+I+J-G-H-I-J=66-46}}}
{{{E+F=20}}}
So the average is,
{{{(E+F)/2=10}}}
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Going back to this equation,
{{{E+F=20}}}
Substitute from 4,
{{{E+(3/2)E=20}}}
{{{(5/2)E=20}}}
{{{E=8}}}
So then,
{{{F=(3/2)8}}}
{{{F=12}}}
From 2,
{{{A+B+C+D+E+F=84}}}
Substituting,
{{{A+B+C+D+20=84}}}
{{{A+B+C+D=64}}}
So the average of the first four is,
{{{(A+B+C+D)/4=16}}}
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Similarly,
{{{E+F+G+H+I+J=66}}}
{{{20+G+H+I+J=66}}}
{{{G+H+I+J=46}}}
{{{(G+H+I+J)/4=46/4}}}
{{{(G+H+I+J)/4=23/2}}}