Question 1055411
solve for x 
{{{sqrt(x-2)=x-4}}}
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<pre>
{{{sqrt(x-2)}}} = {{{x-4}}}.

Square both sides

x - 2 = {{{x^2 - 8x + 16}}}.

{{{x^2 -9x +18}}} = 0.

Factor left side

(x-3)*(x-6) = 0.

The roots are x= 3  and  x= 6.

Only x = 6 satisfies the original equation.

<U>Answer</U>. The solution is x= 6.
</pre>