Question 1055306
{{{(4(8-6)^2-4x3+2x8)/(3^1+19^0)=(4(2)^2-12+16)/(3+1)}}}
{{{(4(8-6)^2-4x3+2x8)/(3^1+19^0)=(4(4)-12+16)/(3+1)}}}
{{{(4(8-6)^2-4x3+2x8)/(3^1+19^0)=(16-12+16)/(3+1)}}}
Now finish the calculation.