Question 1055267
*[illustration lp8.JPG].
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Looks like {{{x=-1}}} and {{{x=4/3}}} are roots so then
{{{x+1}}} and {{{3x-4}}} are factors.
Use polynomial long division to get the remaining polynomial with the complex solution.
{{{Q(x)=(3x^5+2x^4+10x^3+6x^2-25x-20)/((x+1)(3x-4))}}}
{{{Q(x)=x^2+5}}}
So then,
{{{p(x)=(x+1)(3x-4)(x^2+5)}}}