Question 1055242
<pre><b>
{{{log(7,(539))}}}{{{""=""}}}

            539
            / \
           7  77
             / \
            7  11

{{{log(7,(7^2*11))}}}{{{""=""}}}

{{{log(7,(7^2))+log(7,(11))}}}{{{""=""}}}

{{{2*log(7,(7))+log(7,(11))}}}{{{""=""}}}

{{{2*1+log(7,(11))}}}{{{""=""}}}

{{{2+log(7,(11))}}}{{{""=""}}}

Now use the change of base formula:

<font size=1></b><i>[Note: the instructions did not say not to 
use the change of base formula at all.  It 
just meant not to use it on the original 
expression.]</font><b></i> 

{{{2+ln(11)/ln(7)}}}{{{""=""}}} 

{{{2+2.397895273/1.945910149}}}{{{""=""}}}

{{{2+1.232274406}}}{{{""=""}}}

{{{3.232274406}}}

Round to 6 decimal places:

{{{3.232274}}}

Edwin</pre></b>