Question 1055215
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Polygon K has 3 more sides and 2015 more diagonals than polygon N. How many sides does each of these polygons have?
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The key to the solution is this statement:


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      The number of diagonals of the n-sided polygon is {{{(n*(n-3))/2}}}.


It gives you an equation 

{{{((n+3)*n)/2 - (n*(n-3))/2}}} = 2015.

Simplify. 

(n+3)*n - n*(n-3) = 2*2015,

n^2 + 3n - n^2 + 3n = 4030,

6n = 4030.

And since {{{4030/6}}} is not a whole number,
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THE PROBLEM HAS NO SOLUTIONS.