Question 80610
given: sides of pyramid base are {{{4cm}}}, volume is {{{80cm^3}}}

volume of a pyramid; {{{v = (1/3)*h*area of base}}}
area of the base; {{{a = s^2}}}


solve for base area:
{{{a = 4^2}}}
{{{a = 16}}}{{{cm^2}}}


solve for "h" using volume formula:
{{{80 = (1/3)*h*16}}}
{{{5 = (1/3)*h}}}
{{{h = 15}}}{{{cm}}}