Question 1055018
<pre><b>

{{{drawing(400,3200/13,-1,12, -1,7,
locate(5,1.5,50), locate(-.31,.8,5),locate(1.1,3.7,35),

line(0,0,10,0),
line(10,1,10,0),
line(0,0,0,1),
line(0,1,10,1),
line(0,1,2,6),
line(2,6,11,6),
line(11,6,11,5),
line(11,6,10,1),
line(11,5,10,0) )}}}

Area of top side = 50x35 = 1750 cm<sup>2</sup>.
Area of bottom side = 50x35 = 1750 cm<sup>2</sup>.
Area of front side = 50x5 = 250 cm<sup>2</sup>.
Area of back side = 50x5 = 250 cm<sup>2</sup>.
Area of left side = 35x5 = 175 cm<sup>2</sup>.
Area of right side = 35x35 = 175 cm<sup>2</sup>.

Surface area = 1750+1750+250+250+175+175 = 4350 cm<sup>2</sup>

Area of wrapping paper 75 x 60 = 4500 cm<sup>2</sup>

Yes, there is enough wrapping paper to wrap the present.

Edwin</pre>