Question 16886
Given: length is 6 feet longer than twice its width, perimeter is 480 feet.

Let x = width (a)
Let 2x+6 = length (b)

{{{perimeter = 2a + 2b}}}
{{{480 = 2x + 2(2x+6)}}}
{{{480 = 2x + 4x + 12}}}
{{{480 = 6x + 12}}}
{{{468 = 6x}}}
{{{78 = x}}}

therefore, the width of the rectangle is {{{78}}}{{{feet}}}, and the length is {{{2*(78)+6 = 162}}}{{{feet}}}.

Area of a rectangle is A = a*b

{{{a = 78*162}}}
{{{a = 12636}}}{{{ft^2}}}