Question 1055003
Ho: p = 0.68 (claim)
Ha: p ≠  0.68
sample proportion = p-hat = 37/47 = 0.7872
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test stat:: z(0.7872) = (0.7872-0.68)/sqrt[0.68*0.32/47] = 1.58 
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 At = .05, is this hospital's success rate different from the national average
C) No, because the test value 1.58 is in the noncritical region (  we do not reject Ho)
p-value = P(z > 1.58) = 0.057