Question 27898
Given: length is 2 inches longer than twice its width, perimeter is 34 inches.

Let x = width (a)
Let 2x+2 = length (b)

{{{perimeter = 2a + 2b}}}
{{{34 = 2x + 2(2x+2)}}}
{{{34 = 2x + 4x + 4}}}
{{{34 = 6x + 4}}}
{{{30 = 6x}}}
{{{5 = x}}}

therefore, the width of the rectangle is {{{5}}}{{{inches}}}, and the length is {{{2*(5)+2 = 12}}}{{{inches}}}.