Question 19879
Given: length is 10 ft longer than its width, perimeter is 184 ft.

Let x = width (a)
Let x+10 = length (b)

{{{perimeter = 2a + 2b}}}
{{{184 = 2x + 2(x+10)}}}
{{{184 = 2x + 2x + 20}}}
{{{184 = 4x + 20}}}
{{{164 = 4x}}}
{{{41 = x}}}

therefore, the width of the garden is 41 feet, and the length is 41+10 = 51 feet.

Area of a rectangle is A = a*b

{{{a = 41*51}}}
{{{a = 2091}}}{{{ft^2}}}