Question 1054900
Let n be the larger tap. Then the smaller tap would be n+10. So:
1/n+1/(n+10)=1/(75/8)=8/75
75(n+10)+75n=8n²+80n
8n²-70n-750=0
4n²-35n-375=0
(4n+25)(n-15)=0
n=15,-25/4
Throwing out the negative result, we get the bigger tap filling the tank in 15 hours, and the smaller tap in 25 hrs.. &#9786;&#9786;&#9786;&#9786;