Question 1054803
We have 1/m, 1/n, 1/r
:
we know m*n*r is a common denominator for these fractions
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we want the numerator to be m*n*r also so that the fraction is a whole
:
1/m = i/mnr, 1/n = j/mnr, 1/r = k/mnr
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i = nr, j = mr, k = mn, therefore
:
nr + mr + mn = mnr
:
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(nr/mnr) + (mr/mnr) + (mn/mnr) = 1
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