Question 1054748
 I have 12 coins that total the value of $2.25. If there are only quarters and dimes, how many of each kind are there.
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d + q = 12 coins
10d + 25q = 225 cents
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2d + 2q = 24
2d + 5q = 45
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Subtract and solve for "q"::
3q = 21
q = 7 (# of quarters)
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d = 12-q = 12-7 = 5 (# of dimes)
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Cheers,
Stan H.
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