Question 1054495
{{{P(x)/(x^3-2x^2-15x)=G(x)+(2x^2+5x-3)}}}
{{{P(x)/(x(x+3)(x-5))=G(x)+((2x-1)(x+3))}}}
{{{P(x)=G(x)*x(x+3)(x-5)+x(2x-1)(x+3)^2(x-5)}}}
So when you divide by {{{(x+3)}}}
{{{P(x)/(x+3)=G(x)*x(x-5)+x(2x-1)(x+3)(x-5)}}}
So there is no remainder.