Question 1054634
Is the 3% compounded monthly? Quarterly? Annually? I will assume it's compounded monthly
:
n = number of withdrawals(we will find this number)
A = present value 160,000
P = monthly payment 600
i = interest monthly 0.03/12 = 0.0025
:
n = log[P/(P-A*i)]/log(1+i)
n = log[600/(200-15000*.0025)]/log(1.0025) = 
n = log(600/162.5)/0.0025
n = 0.5673/0.0025 = 226.92
:
I think the numbers are correct. Good luck.