Question 1054563
Take log of both sides and change one of them using Change of Base formula.




Another way is just use log base ten.


{{{log(10,4^(1-3x))=log(10,5^(0.5x+7))}}}


{{{(1-3x)*log((4))=(0.5x+7)log((5))}}}


{{{log((4))-3*log((4))x=0.5*log((5))x+7*log((5))}}}


{{{log((4))=0.5*log((5))x+3*log((4))+7*log((5))}}}


{{{log((4))-7*log((5))=x(0.5*log((5))+3*log((4)))}}}


{{{highlight((log((4))-7*log((5)))/(0.5*log((5))+3*log((4)))=x)}}}
Look in your reference information for those logarithms, base ten, and do the computations for x.