Question 1054568
When the slower runner goes around the track once,
the faster runner will be 
{{{ ( 1/6 )( 8 - 6 ) = 2/6 }}}
{{{ 2/6 = 1/3 }}}  mi ahead
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When the slower runner goes completely around
amnother time, the faster runner will be {{{ 1/3 + 1/3 = 2/3 }}}
of a mile ahead
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When the slower runner goes around a 3rd time,  the 
faster runner will be {{{ 3*(1/3) = 1 }}} mile ahead,
which puts them both at the starting line.
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The time for this is the time for 3 laps by the slower runner
{{{ 3*8 = 24 }}} minutes