Question 1054553
{{{h=b-6}}}
{{{A=(1/2)bh=260}}}
Substituting,
{{{(1/2)b(b-6)=260}}}
{{{b^2-6b=520}}}
{{{b^2-6b+9=520+9}}}
{{{(b-3)^2=529}}}
{{{b-3=0 +- 23}}}
{{{b=3 +- 23}}}
Since the base must be positive,
{{{b=26}}}{{{yds}}}
{{{h=26-6=20}}}{{{yds}}}