Question 1054534
{{{M^A=M^(-1)=1/M}}}
{{{(L/T)^B=(L/T)^(-2)=(T/L)^2=T^2/L^2}}}
{{{L^C=L^1=L}}}
So then putting it all together,
{{{M^A*(L/T)^B*L^C=(1/M)(T^2/L^2)(L)}}}
{{{M^A*(L/T)^B*L^C=T^2/(ML)}}}
You also know {{{V=L/T}}} and 
{{{1/V=T/L}}}
{{{1/V^2=T^2/L^2}}}
{{{L/V^2=T^2/L}}}
So then substituting,
{{{M^A*(L/T)^B*L^C=(1/M)(T^2/L)}}}
{{{M^A*(L/T)^B*L^C=(1/M)(L/V^2)}}}
{{{M^A*(L/T)^B*L^C=L/(MV^2)}}}