Question 1054386
{{{3-7x=6x^2}}}
{{{6x^2+7x-3=0}}}
{{{(2x+3)(3x-1)=0}}}
Two possible solutions:
{{{2x+3=0}}}
{{{2x=-3}}}
{{{x=-3/2}}}
and
{{{3x-1=0}}}
{{{3x=1}}}
{{{x=1/3}}}
Verify that the possible solutions lead to positive arguments for the log function for the left hand side since right hand side is squared,
{{{3-7x=3-7(-3/2)=3+21/2=27/2}}} 
Good solution.
{{{3-7(1/3)=9/3-7/3=2/3}}}
Good solution.