Question 1054319
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Hey. {{{tan (195)}}}
I got figured it would be something with {{{pi+pi/4-pi/6}}} but I am unsure how to go based on the sum and difference identities. 
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tan(195°) = tan(15°) = {{{tan(45^o-30^0)}}} = 2 - sqrt(3).



By the way, ignore writing by "josgarithmetic".
It is wrong.