Question 92083
Assume you mean, (a couple sets of brackets would help a lot here):
{{{((x+3))/2}}} - {{{((x-8))/6}}} = 3
:
Multiply by 6 to get rid of the denominators
{{{(6(x+3))/2}}} - {{{(6(x-8))/6}}} = 6(3)
Resulting in:
3(x+3) - (x-8) = 18
:
3x + 9 - x + 8 = 18; a neg outside the brackets changes the sign inside the brackets
:
2x + 17 = 18
:
2x = 18 - 17
:
x = 1/2
:
x = .5
:
:
Check solution in original equation:
{{{((.5+3))/2}}} - {{{((.5-8))/6}}} = 3 
:
{{{((3.5))/2}}} - {{{((-7.5))/6}}} = 3
:
1.75 - (-1.25) = 3; minus a minus is a plus