Question 91882
Solve
{{{2z/5}}} = {{{z - 1/3}}}
:
Multiply equation by 15 to get rid of those denominators, resulting in:
3(2z) = 15z - 5(1)
:
6z = 15z - 5
:
+5 = 15z - 6z
:
5 = 9z
:
z = 5/9
:
:
Check solution in original equation:
{{{2(5/9)/5}}} = {{{(5/9) - 1/3}}}
{{{10/9/5}}} = {{{(5/9) - 1/3}}}
{{{2/9}}} = {{{5/9 - 3/9}}}