Question 1054085
{{{(8xy^3z)/(2^(-2)x^(-3)y^(0)z)=(8/(1/4))x^(1-(-3))y^(3-0)z^(1-1)}}}
{{{(8xy^3z)/(2^(-2)x^(-3)y^(0)z)=32x^(1+3)y^(3)z^(0)}}}
{{{(8xy^3z)/(2^(-2)x^(-3)y^(0)z)=32x^(4)y^(3)}}}