Question 1054051
0.05 significance level
(a)	State the null hypothesis and the alternate hypothesis. (Round your answers to 2 decimal places.) 
sample proportion = p-hat = 3/60 = 1/20 = .05
Ho: p =	.10

Ha: p ≠ .10

(b)	
State the decision rule for 0.05 significance level. (Negative amounts should be indicated by a minus sign. Round your answers to 2 decimal places.) 
H0 is rejected if z is not between -1.96 and 1.96
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(c-1)	
Compute the value of the test statistic. (Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places.) 
test stat:: z(0.05) = (0.05-0.1)/sqrt[0.1*0.9/60] = -.05/.0387 = -1.291
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(c-2)	What is your decision regarding H0? -1.291 > -1.96  Do not Reject
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(d)	Determine the p-value. (Round your answer to 4 decimal places.) 
p-value	= InvNorm(-1.291) = .0984