Question 1054156
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Two airplanes depart from an airport traveling in opposite directions. The second airplane is 200 miles per hour faster 
than the first. After 2 hours they are 1100 miles apart. Find the speeds of the airplanes?
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<pre>
2*(x + (x+200)) = 1100.    (It is the "distance" equation D = R*T)
                           (Here "x" is the speed of the slowest plane)

Simplfy and solve for x:

2x + 2x + 400 = 1100  --->

4x = 1100-400,

4x = 700   --->  x = {{{700/4}}} = 175 mph.

<U>Answer</U>.  The speed of the slowest plane is 175 mph.
         The speed ot the other plane is 175+200 = 375 mph.

<U>Check</U>.  2*(175+375) = 2*550 = 1100.   Correct!
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