Question 1054099
The slope of the parallel line is the same, -3/2
point slope formula is y-y1=m(x-x1), where (x1,y1) is point
y-(-2)=-3/2(x-6)
Y+2=(-3/2)x+9
y=(-3/2)x+7' when x=6, y=-9+7=-2
{{{graph(300,300,-10,10,-10,10,(-3x/2)+6,(-3x/2)+7)}}}