Question 1054065
95% confidence interval
x̄ =4334, n = 32 and σ= 864
ME = ± {{{ z*sigma/sqrt(n)}}}, z = invNorm(.975) = 1.96
ME = ± {{{ 1.96*864/sqrt(32)}}}
confidence interval for the population mean ( (rounded to two decimal places) 
4334 - ME < {{{mu}}} < 4334 + ME
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 = CI	z = value
90%	z =1.645
92%	z = 1.751
95%	z = 1.96
98%	z = 2.326
99%	z = 2.576