Question 1054066
98% confidence interval
x̄ =80, n = 99  and σ= 20
ME = ± {{{ z*sigma/sqrt(n)}}}, z = invNorm(.99) = 2.326
ME = ± {{{ 2.326*20/sqrt(99)}}}
confidence interval for the population mean ( (rounded to two decimal places) 
80- ME < {{{mu}}} < 80 + ME
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 = CI	z = value
90%	z =1.645
92%	z = 1.751
95%	z = 1.96
98%	z = 2.326
99%	z = 2.576