Question 92088
L has y-intercept (0,-3)and is parallel to the line with equation y=2/3x+1.
Parallel lines have equal slopes.  The slope-intercept form of a line is:  {{{highlight(y=mx+b)}}}, where m=slope and (0,b)=y-intercept.
The slope of {{{y=(2/3)x+1}}} is m=2/3.  Therefore, your line also has a slope of m=2/3.
So m=2/3 and (0,b)=(0,-3), plug them into the slope-intercept form of the line and you have:
{{{y=(2/3)x+(-3)}}}
{{{highlight(y=(2/3)x-3)}}}
Happy Calculating!!!