Question 1054037
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Want to know how to make a paper crane?  Go here:

https://www.youtube.com/watch?v=pqeI94Jri1M
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The number of paper cranes that Thomas has is 8 times that of Raymond.
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So

T = 8R
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If Thomas gives 28 paper cranes to Raymond, 
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then Thomas will have T-28 paper cranes, 
and Raymond will have R+28
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they will have the same number of paper cranes. 
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So T-28 = R+28

That gives us this system of two equations in
two unknowns:

{{{system(T=8R,T-28=R+28)}}}

Solve that by substituting 8R from the first equation
for T in the second equation:

8R-28 = R+28
   7R = 56
    R = 8

The substitute 8 for R in T=8R

T = 8(8)
T = 64

Let's check that so far:
The number of paper cranes that Thomas has, which is 64,
is 8 times that of Raymond, which is 8. 

If Thomas gives 28 paper cranes to Raymond, then Thomas
will have only 64-28 or 36, and Raymond will have 8+28 or 36,
so they will have the same number of paper cranes. 

So it is correct.  But the question is:
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How many paper cranes do they have altogether?
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They have 8+64 or 72 paper cranes altogether.

Edwin</pre>