Question 1054008
Let {{{ t }}} = time in hrs he takes
driving at {{{ 2222 }}} mi/hr
Let {{{ d }}} = the distance between the cities in miles
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(1) {{{ d = 2222t }}}
(2) {{{ d = 4040*( t - 99 ) }}}
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Substitute (1) into (2)
(2) {{{ 2222t = 4040*( t - 99 ) }}}
(2) {{{ 2222t = 4040t - 399960 }}}
(2) {{{ 1818t = 399960 }}}
(2) {{{ t = 220 }}}
and
(1) {{{ d = 2222t }}}
(1) {{{ d = 2222*220 }}}
(1) {{{ d = 488840 }}}
The driving distance is 488, 840 mi
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check:
(2) {{{ d = 4040*( t - 99 ) }}}
(2) {{{ 488840 = 4040*( 220 - 99 ) }}}
(2) {{{ 488840 = 4040*121 }}}
(2) {{{ 488840 = 488840 }}}
OK