Question 1053928
Volume(Vs) of a sphere = (4/3) * pi * r^3, where r is the radius and pi is (22/7)
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I assume that the problem's spherical segment has one base
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V(ss) = (1/3) * pi * h^2 * (3R - h), where h is the height, R is the radius
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904.78(Vs) = (4/3) * (22/7) * r^3
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r^3 = 904.78 * 21 / 88
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r = 5.9992 m
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V(ss) = (1/3) * (22/7) * 4^2 * (3*5.9992-4) = 234.6264 approx 234.63
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The volume of spherical segment is 234.63 cu m
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