Question 1053977
For a square:
{{{ A = s^2 }}} ft2
where {{{ A }}} = area 
{{{ s }}} = a side of the square
{{{ s = sqrt(A) }}} ft
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{{{ A = 50 }}} ft2
{{{ s = sqrt( 50 ) }}} ft
{{{ s = 5*sqrt(5) }}} ft
{{{ s = 5*2.2361 }}} ft
{{{ s = 11.2 }}} ft