<PRE><B>Question 1053953</B>
how many liters of a 5% acidic solution must be mixed with a 20% acidic solution to make 100 L having a 14% concentration 
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acid + acid = acid
0.05x + 0.20(100-x) = 0.14*100
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5x + 20*100 - 20x = 14*100
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-15x = -6*100
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x = 40 L (amt. of 5% solution needed)
100-x = 60 L (amt. of 20% solution needed)
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Cheers,
Stan H.
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