Question 91987
the denominator on the right side is the common denominator for the two fractions on the left side


so (k+2)+(k-1)=3 ... 2k+1=3 ... 2k=2 ... k=1


BUT ... if k=1 then two of the denominators become 0, resulting in undefined quantities


this means that there is NO SOLUTION ... the solution set is the null set