Question 1053728
hypotenuse is x
one leg ix x-4
the other is x-2
The square of each leg added equals the square of the hypotenuse
(x-4)^2+(x-2)^2=x^2=x^2-8x+16+x^2-4x+4
x^2=2x^2-12x+20
0=x^2-12x+20
(x-10)(x+2)=0
x=10, and -2, whic
h is ignored
The legs are 6 and 8 meters, and
10 meters is the hypotenuse length.