Question 91977
let w=width, so w+1=length ... the length, width, and diagonal form a right triangle with the diagonal as the hypotenuse


by Pythagoras, w^2+(w+1)^2=4^2 ... 2w^2+2w+1=16 ... 2w^2+2w-15=0 ... {{{w=(-2 +- sqrt(4-(4)(2)(-15)))/(2(2))=(-2 +- sqrt(124))/4=(-1 +- sqrt(31))/2}}}


so w=2.28 and w=-3.28 ... the negative value is not realistic ... length=3.28