Question 1053512
Need to know re Margin of Error:
ME =± {{{ z*sigma/sqrt(n)}}}
0r
ME =±  {{{z*sqrt((p(1-p))/n)}}}
|In this ex, with info given

95% confidence interval
ME =±  {{{ z*sigma/sqrt(n)}}}
z = invNorm( 95 +.05/2) 0r z =invNorm(.05/2)  
z = ± 1.96
ME = ±  {{{ 1.96*5.4/sqrt(91)}}} ***
95% confidence interval
55 ± ME