Question 1053428
{{{ 2*log( x + 6 ) = log( 36 ) + log( 4 ) }}}
{{{ log( ( x + 6 )^2 )  = log( 36*4 ) }}}
{{{ ( x + 6 )^2 = 144 }}}
{{{ x^2 + 12x + 36 = 144 }}}
By observation:
{{{ x^2 + 12x + 6^2 = 12^2 }}}
{{{ ( x + 6 )^2 = 12^2 }}}
{{{ x + 6 = 12 }}}
{{{ x = 6 }}}
and, also, taking the negative square root of {{{ 12^2 }}},
{{{ x + 6 = -12 }}}
{{{ x = -18 }}}
This 2nd answer cannot be used because that would
result in {{{ 2*log(( -18 + 6 )) = 2*log(( -12 )) }}} and
you cannot get a negative result by raising a positive base
to either a + or a - log
So the answer is {{{ x = 6 }}}