Question 1053391
ME = {{{z*sqrt((p(1-p))/n)}}}
z = 1.645 and p = 2250/4000 = .5625
ME = {{{1.645*sqrt((.5625(.4375))/4000)}}} round to the nearest ten-thousandth. 
2250 ± ME
|
 = CI	z = value
90%	z =1.645
92%	z = 1.751
95%	z = 1.96
98%	z = 2.326
99%	z = 2.576