Question 1053003
Distributive property,
{{{(pq-4)^3=(pq-4)^2(pq-4)}}}
{{{(pq-4)^3=(p^2q^2-8pq+16)(pq-4)}}}
{{{(pq-4)^3=p^2q^2(pq-4)-8pq(pq-4)+16(pq-4)}}}
{{{(pq-4)^3=p^3q^3-4p^2q^2-8p^2q^2+32pq+16pq-64}}}
{{{(pq-4)^3=p^3q^3-12p^2q^2+48pq-64}}}