Question 1053120
Let the integers be {{{N-4}}},{{{N-2}}},{{{N}}},{{{N+2}}},{{{N+4}}}.
{{{5(N-4)=N-2+N+N+2+N+4}}}
{{{5N-20=4N+4}}}
{{{N=24}}}
So the integers are 20, 22, 24, 26, and 28.